Full Moon To Light Up Ohio Skies On 4th Of July

CLEVELAND — A nearly-full "Buck Moon," will illuminate the Ohio sky on July 4th, according to the Farmers' Almanac.

With the continued threat of COVID-19, many Ohio communities have cancelled their Independence Day festivities, including fireworks displays. However, a nearly-full moon will now be clearly visible in the night sky, the publication said.

The Buck Moon will be full on July 5, but will appear full when it rises after sunset on Independence Day, the Farmers' Almanac said.

"In fact, it will appear full for a day or two surrounding its full phase (most people don't notice the difference between a 98% illuminated Moon and one that is 100% illuminated). As it rises higher, it will adorn the sky and provide us with its magical glow for the holiday celebration — provided there are no clouds or storms to hinder its view," the publication said.

Current forecasts, predict a warm and dry Independence Day weekend for much of Ohio. Night skies should be clear and provide ample space to see stars and the (nearly) full moon. Temperatures will hit the upper 80s before dropping into the 70s overnight.

The Farmers' Almanac group released a YouTube video explaining the name Buck Moon.